Question

$\text{Find the zeros of the quadratic}\text{polynomial}{x}^2-8x+12.$

• A. $2\text{and}6$
• B. $8\text{and}4$
• C. $10\text{and}2$
• D. $4\text{and}5$

Answer 1

The correct option is A

$2\text{and}6$

To find the zeroes, equate the polynomial to zero and then factorise.

$\therefore x^2-8x+12=0$

$\Rightarrow x^2-6x-2x+12=0$

$\Rightarrow x(x-6)-2(x-6)=0$

$\Rightarrow (x-6)(x-2)=0$

$\Rightarrow x-6=0\text{or}x-2=0\Rightarrow x=6;2$

$2\text{and}6\text{are the zeros of the quadratic}\text{polynomial.}$