$Find x if$ $l o g_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3$

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Solution

$l o g_{10} (x + 1) (x - 1) = l o g_{10} 11 + l o g_{10} 3^{2}$

$l o g (x^{2} - 1) = l o g (11 \times 9)$

$x^{2} - 1 = 99$

$x^{2} = 100$

$x = 10$

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Similar questions

{log}_{10} (x + 1) + {log}_{10} (x - 1) = {log}_{10} 11 + 2 {log}_{10} 3

x

{log}_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3

{log}_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3

f (x) = | \begin{matrix} {log}_{10} x \end{matrix} |

x = 1

l o g_{10} x - l o g_{10} \sqrt{x} = \frac{2}{l o g_{10} x}

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