$Find x if$ $l o g_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3$

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100

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Solution

The correct option is A
10

$l o g_{10} (x + 1) (x - 1) = l o g_{10} 11 + l o g_{10} 3^{2}$

$l o g (x^{2} - 1) = l o g (11 \times 9)$

$x^{2} - 1 = 99$

$x^{2} = 100$

$x = 10$

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Similar questions

$Find x if$ $l o g_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3$

{log}_{10} (x + 1) + {log}_{10} (x - 1) = {log}_{10} 11 + 2 {log}_{10} 3

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{log}_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3

{log}_{10} (x + 1) + l o g_{10} (x - 1) = l o g_{10} 11 + 2 l o g_{10} 3

If ${log}_{10} 5 + {log}_{10} (5 x + 1) = {log}_{10} (x + 5) + 1$ , then $x$ is equal to

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