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Byju's Answer
Standard XII
Mathematics
Linear Programming Problems
Given equatio...
Question
Given equation:
300
y
=
500
x
+
1900
where 'x' = time (hours)
and 'y' = Intensity (in cd)
For plotting the graph of the equation, fill the table with the correct value of
p
and
q
obtained from the graph.
A
p
=
8
a
n
d
q
=
5
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B
p
=
8
a
n
d
q
=
13
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C
p
=
−
8
a
n
d
q
=
−
5
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D
p
=
3
a
n
d
q
=
8
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Solution
The correct option is
B
p
=
8
a
n
d
q
=
13
Given equation:
300
y
=
500
x
+
1900
Put the given value of x from the table in the respective equation and find the corresponding unknown values.
If you put
x
=
1
,
then the value of y from
the equation is:
⇒
300
y
=
500
×
1
+
1900
⇒
300
y
=
500
+
1900
=
2400
⇒
y
=
2400
300
=
8
So, value of p will be 8.
∴ (1,8) will be a point on the straight line in the graph.
Similarly if you put
x
=
4
,
then the value of y
from the equation is:
⇒
300
y
=
500
×
4
+
1900
=
2000
+
1900
⇒
y
=
3900
300
=
13
So, value of q will be 13.
∴ (4,13) will be a point on the straight line in the graph.
The plotting of the graph is shown as:
∴ The table can be filled as:
x
1
4
y
8
13
Suggest Corrections
0
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