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Question

Given the area of rectangle is A=25a235a+12. The length is given as (5a3).Find the width of the rectangle.


A

5a3

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B

5a4

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C

4a5

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D

a4

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Solution

The correct option is B

5a4


Let y be the width.
Given: Area =25a235a+12

We know that, area of a rectangle = Length ×breadth

Hence, y×(5a3)=25a235a+12
y=(25a235a+12)÷(5a3)
By long division method,

5a35a4)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯25a235a+12 25a215a + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 20a+12 20a+12 + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0
y=5a4Width of the rectangle =5a4


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