Given the area of rectangle is A=25a2−35a+12. The length is given as (5a−3).Find the width of the rectangle.
5a−4
Let y be the width.
Given: Area =25a2−35a+12
We know that, area of a rectangle = Length ×breadth
Hence, y×(5a−3)=25a2−35a+12
y=(25a2−35a+12)÷(5a−3)
By long division method,
5a−35a−4)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯25a2−35a+12 25a2−15a − + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ −20a+12 −20a+12 + − ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0
∴y=5a−4Width of the rectangle =5a−4