Question

$\text{Given the area of rectangle is}A=25a^2-35a+12.\text{The length is given}\text{as}(5a-3).\text{Find the width of the}\text{rectangle.}$

• A. $4a-5$
• B. $5a-3$
• C. $5a-4$
• D. $a-4$

Answer 1

The correct option is C

$5a-4$

$\text{Let y be the width.}$
$\text{Given: Area}=25a^2-35a+12$

$\text{We know that, area of a rectangle}$$\text{= Length}\times \text{breadth}$

$\text{Hence,}y\times (5a-3)=25a^2-35a+12$
$y=(25a^2-35a+12)÷(5a-3)$
By long division method,

$5a-3\stackrel{5a-4}{)\overline{25a^2-35a+12}}25a^2-15a-+\overline{}-20a+12-20a+12+-\overline{}0$
$\therefore y=5a-4\text{Width of the rectangle =}5a-4$