$How many bricks will be required to construct a wall 8 m long,6m high and 22.5 cm thick if each brick measures 25 m \times 11.25 c m \times 6 c m . ?$

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Solution

Wall;
l=8m=800cm
h=6m=600cm
b=22.5cm
volume of the wall=lbh
=800 x 600 x 22.5
=10800000 $c m^{3}$
brick;
l=25cm
b=11.25cm
h=6cm
volume=lbh
=25 x 11.25 x 6
=1687.5 $c m^{3}$
therefore the number of bricks = $\frac{v o l u m e o f w a l l}{v o l u m e o f 1 b r i c k}$
= $\frac{10800000}{1687.5}$
= 6400 bricks
Therefore, 6400 bricks will be required to construct a wall 8 m long,6m high and 22.5 cm thick.

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