If 6ax−9ax5+1=4x+89,find x, when a = 2
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6ax−9ax5+1=4x+89⇒6ax−9ax5−4x5=89−1⇒30ax−9ax−20x5=88⇒21ax−20x=5×88⇒x(21a−20)=440⇒x=44021a−20Given a=2∴x=44042−20=44022⇒x=20
Given, 6ax−9ax5+1=4x+89 Find x, when a=2
A woman increased her weight by 5:4. Her original weight is 60kg. Find her increase in weight.
Find the value of k if x + y + 5 = 0 is a tangent to the circle x2+y2+10x+2ky+10=0
If √5n=125 then find the value of 5n√64.