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B
[043−8]
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C
[04−83]
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D
[303−8]
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Solution
The correct option is B[043−8] A+2B=[2−416]⋯(i)AT+BT=[120−1](AT+BT)T=[120−1]TA+B=[102−1]⋯(ii)
Now, (i)−(ii) B=[2−416]−[102−1]B=[1−4−17]∴A=[102−1]−[1−4−17]A=[043−8]∴A=[043−8]