If a=14(2x−1),b=−15(4x+1), a-b=2, find the value of x.
3
8
6
11
None of these
a=14(2x−1),b=−15(4x+1)⇒14(2x−1)−{−15(4x+1)}=2⇒2x−14+4x+15=2⇒5(2x−1)+4(4x+1)20=2⇒10x−5+16x+4=40⇒26x−1=40⇒26x=41⇒x=4126=11526
If a=14(2x−1),b=−15(4x+1), a-b=2, Find the value of x.
The common factors of 3b, 33ab is/are
tan−1a+tan−1b, where a>0,b>0,ab>1, is equal to