If A={x:x∈R, x2=16 and 2x=6}, then A = ___.
∅
{∅}
{3}
{-4, 3, 4}
x2=16⇒x=±4
2x=6 ⇒x=3
There is no value of x which satisfies both of the above equations.
Thus, A = ∅ or { }.
The set A={x:xϵR,x2=16 and 2x=6} equals