If[2x+y4x5x−74x]=[77y−13yx+6] then the value of x,y is,
A
x=3;y=3
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B
x=2;y=4
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C
x=3;y=1
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D
x=2;y=3
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Solution
The correct option is Dx=2;y=3 Given[2x+y4x5x−74x]=[77y−13yx+6]
Comparing the corresponding elements, we get 4x=x+6 ⇒3x=6 ⇒x=2 2x+y=7 ⇒y=7−2x ⇒y=7−4 ⇒y=3
Hence, the value of x,y are 2,3 respectively.
So option (b) is correct.