If cos 3- -3-2- 0- - 3- - 90- then find the value of -

Given: cos3 θ=√(3)/2 We know that cos 30^∘=√(3)/2 Comparing the two we get, 3θ nbsp;= 30^∘.... (given nbsp;0^∘ lt; 3θ lt; 90^∘) ⇒ nbsp;θ nbsp;= 10 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Trigonometric Ratios

If cos 3θ= √3...

Question

$If c o s 3 θ = \frac{\sqrt{3}}{2}$ , 0° < $3 θ$ < 90°, then find the value of $θ$ .

15°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10°

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
10°

Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$

Suggest Corrections

Similar questions

$If c o s 3 θ = \frac{\sqrt{3}}{2}$ , 0° < $3 θ$ < 90°, then find the value of $θ$ .

Q. If cos

3 θ = \frac{\sqrt{3}}{2}; 0 < θ < 20^{\circ}

then the value of

θ

is:

Q. Find the value of

θ

in degrees for

2 cos 3 θ = 1

3 θ

is acute.

Q. If

sin 3 θ = cos (θ - 6^{o})

and

3 θ

and

θ - 6^{o}

are acute angles, find the value of

θ

cos θ + cos 7 θ + cos 3 θ + cos 5 θ = 0

Find the value of

θ

Join BYJU'S Learning Program

If cos 3θ=√32, 0° < 3θ < 90°, then find the value of θ.

The correct option is B 10° Given: cos3θ=√32 We know that cos30∘=√32 Comparing the two we get, 3θ=30∘.... (given 0∘ < 3θ < 90∘) ⇒θ=10∘

$If c o s 3 θ = \frac{\sqrt{3}}{2}$ , 0° < $3 θ$ < 90°, then find the value of $θ$ .

The correct option is B
10°

Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$