If cos 3- -3-2- 0- - 3- - 90- then find the value of -

Given: cos3 θ=√(3)/2 We know that cos 30^∘=√(3)/2 Comparing the two we get, 3θ nbsp;= 30^∘.... (given nbsp;0^∘ lt; 3θ lt; 90^∘) ⇒ nbsp;θ nbsp;= 10 ...

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Byju's Answer

Standard X

Mathematics

Trigonometric Ratios

If cos 3θ= √3...

Question

$If c o s 3 θ = \frac{\sqrt{3}}{2}$ , 0° < $3 θ$ < 90°, then find the value of $θ$ .

15°

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10°

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0°

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12°

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Solution

The correct option is B
10°

Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$

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If cos 3θ=√32, 0° < 3θ < 90°, then find the value of θ.

The correct option is B 10° Given: cos3θ=√32 We know that cos30∘=√32 Comparing the two we get, 3θ=30∘.... (given 0∘ < 3θ < 90∘) ⇒θ=10∘

$If c o s 3 θ = \frac{\sqrt{3}}{2}$ , 0° < $3 θ$ < 90°, then find the value of $θ$ .

The correct option is B
10°

Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$