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Question

If ΔABC is similar to ΔPQR such that 2AB=PQ and BC=6 cm,then QR is equal to:

[1 Mark]

A
3 cm
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B
6 cm
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C
9 cm
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D
12 cm
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Solution

The correct option is D 12 cm
Given,

ΔABC is similar to ΔPQR such that 2AB=PQ and BC=6 cm,


ABCPQR
ABPQ=BCQR
(Ratio of corresponding sides of similar triangles are equal)

AB×QR=BC×PQ
AB×QR=BC×2AB
QR=2BC=2×6=12cm

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