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Question

If 58×43×23=A, compare the value of A with 1

A
A<1
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B
A>1
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C
A=1
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D
Cannot be determined.
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Solution

The correct option is A A<1
Calculating 58×43×23 we get:

58×43×23

=(58×43)×23

=5×48×3×23

=2024×23

=20×224×3

=4072

=40÷872÷8

=59

Now, 5<9

59<99

59<1

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