If fx-max -2 sin y-x- where y - R- then minimum value of fx is

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f(x) Transforms to |f(x)|

If fx=max |2 ...

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$If f (x) = max | 2 sin y - x | (where y \in R), then minimum value of f (x) is$

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If f (x) = max | 2 sin y - x | (where y \in R), then minimum value of f (x) is

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f:N \to Y

f (x) = x^{2},

W h e r e Y = {y : y = x^{2}, x \in N}

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