If fx-x-1- find ddxf- fx-

F(x)=x+1 ⇒ (f ∘ f)(x)=(x+1)+1=x+2 Now, differentiating with respect to x, we get ddx(f∘ f)(x)=ddx(x+2)=1 ...

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If fx=x+1, fi...

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$If f (x) = x + 1, find \frac{d}{d x} (f \circ f) (x) .$

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If f (x) = x + 1, find \frac{d}{d x} (f \circ f) (x) .

f (x) = (2 x - π)^{3} + 2 x - cos x

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x = π

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{[\frac{d}{d x} (f^{- 1} (x))]}_{x = f (1)}

f (x) = x^{2} + x + 1

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f (x) = \frac{x}{1 + x}

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