If 3x-5-4-1-x-3-6- then find the value of x-

Given : 3x+5/4+1=x+3/6 By taking the LCM, we get nbsp; nbsp;3x+5+4/4 nbsp; = x+3/6 nbsp; nbsp; 3x+9/4 nbsp; = x+3/6 On cross multiplication, we ...

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Standard XII

Chemistry

Liquids in Liquids

If 3x+5/4+1=x...

Question

$If \frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}, then find the value of x .$

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Solution

The correct option is B
- 3

$Given : \frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}$

By taking the LCM, we get

$\frac{3 x + 5 + 4}{4} = \frac{x + 3}{6} \frac{3 x + 9}{4} = \frac{x + 3}{6}$
On cross multiplication, we get
$6 \times (3 x + 9) = 4 \times (x + 3)$
$18 x + 54 = 4 x + 12 18 x - 4 x = 12 - 54 14 x = - 42 x = \frac{- 42}{14} x = - 3$

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$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. If

\frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}

, then the value of '

x

' is

$If \frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}, then find the value of x .$

$If \frac{(8 x + 1)}{(3 x + 2)} = 2, then find the value of x.$

Q. If

\frac{3 x^{2} - 2 x + 4}{(x - 1)^{2}} = \frac{A_{1}}{x + 1} + \frac{A_{2}}{(x + 1)^{2}} + \frac{A_{3}}{(x + 1)^{3}} + \frac{A_{4}}{(x + 1)^{4}} + \frac{A_{5}}{(x + 1)^{5}} + \frac{A_{6}}{(x + 1)^{6}}

, then

(A_{1} + A_{3} + A_{5}, A_{2} + A_{4} + A_{6}) =

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If 3x+54+1=x+36, then find the value of x.

The correct option is B - 3 Given : 3x+54+1=x+36 By taking the LCM, we get 3x+5+44 = x+36 3x+94 = x+36 On cross multiplication, we get 6×(3x+9)=4×(x+3) 18x+54=4x+1218x−4x=12−5414x=−42x=−4214x=−3

$If \frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}, then find the value of x .$