Question

$\text{If one of the zeros of quadratic polynomial}(k-1)x^2+kx+1\text{is}-3,$
$\text{then find the value of}k.$

• A. $\frac{4}{3}$
• B. $-\frac{4}{3}$
• C. $\frac{2}{3}$
• D. $-\frac{2}{3}$

Answer 1

The correct option is A $\frac{4}{3}$

$\text{Given:}p\left(x\right)=(k-1)x^2+kx+1\text{and -}p(-3)=0$

$\therefore (k-1)(-3{)}^2+k(-3)+1=0=9(k-1)-3k+1=0=9k-9-3k+1=0=6k-8=0=6k=8\Rightarrow k=\frac{8}{6}=\frac{4}{3}$