If→aand→b are mutually perpendicular unit vectors, then (3→a+2→b)⋅(5→a−6→b)=
A
5
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B
3
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C
6
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D
12
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Solution
The correct option is B3 →aand→b are perpendicular. ⇒→a⋅→b=→b⋅→a=0 Also,|→a|=|→b|=1 Now,(3→a+2→b)⋅(5→a−6→b) =3→a⋅(5→a−6→b)+2→b(5→a−6→b) =15|→a|2−18→a⋅→b+10→b⋅→a−12|→b|2 =15−12=3