If p and q are the roots ofax2-bx-c-0-a 0-then find the value ofp - q-

𝐅𝐢𝐧𝐝 𝐭𝐡𝐞 𝐯𝐚𝐥𝐮𝐞 𝐨𝐟 𝐩+𝐪:0ex0exHere p and q are the roots. then,0ex0exSum of the roots = p + q0ex0exFor a quadratic polynomial0ex0ex[ Sum of the roots = ...

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Standard X

Mathematics

Introduction to Similar Triangles

If p and q ar...

Question

$Ifpandqaretherootsof a x^{2} - b x + c = 0, a \neq 0, thenfindthevalueof p + q .$

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Solution

$Findthevalueofp+q: Here p and q aretheroots.then, Sumoftheroots = p + q Foraquadraticpolynomial \begin{matrix} Sumoftheroots & = \frac{- b}{a} \\ p + q & = - (\frac{- b}{a}) = \frac{b}{a} \end{matrix} Hence,thevalueof p + q is \frac{b}{a}; a \neq 0 .$

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Ifpandqaretherootsofax2-bx+c=0,a≠0,thenfindthevalueofp+q.

Findthevalueofp+q:Herepandqaretheroots.then,Sumoftheroots=p+qForaquadraticpolynomialSumoftheroots=-bap+q=-(-ba)=baHence,thevalueofp+qisba;a≠0.

$Ifpandqaretherootsof a x^{2} - b x + c = 0, a \neq 0, thenfindthevalueof p + q .$

$Findthevalueofp+q: Here p and q aretheroots.then, Sumoftheroots = p + q Foraquadraticpolynomial \begin{matrix} Sumoftheroots & = \frac{- b}{a} \\ p + q & = - (\frac{- b}{a}) = \frac{b}{a} \end{matrix} Hence,thevalueof p + q is \frac{b}{a}; a \neq 0 .$