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Question

If sin3α+8cos3β+1=6sinαcosβ where α,β[0,π2], then the value of α+βαβ is

A
12
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B
2
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C
1
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D
5
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Solution

The correct option is D 5
If we considersin3α, 8cos3β and 1as 3 individual terms, then :-A.M.=sin3α+8cos3β+13G.M.=3sin3α×8cos3β×1=2sinαcosβ A.M.=G.M. (Acc. to eqn. given. All the individual terms are equal,sin3α=1, 8cos3β=1α=π2, β=π3α+βαβ=5

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