If sin3α+8cos3β+1=6sinαcosβwhereα,β∈[0,π2], then the value of α+βα−β is
A
12
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B
2
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C
1
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D
5
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Solution
The correct option is D5 If we considersin3α,8cos3βand 1as 3 individual terms, then :-A.M.=sin3α+8cos3β+13G.M.=3√sin3α×8cos3β×1=2sinαcosβ⇒A.M.=G.M.(Acc. to eqn. given.⇒ All the individual terms are equal,⇒sin3α=1,8cos3β=1⇒α=π2,β=π3⇒α+βα−β=5