If sum of the roots of the equation(a+1)x2−(2a+3)x+(3a+4)=0 is −2,then the product of the roots is
1
-1
2
-2
α+β=2a+3a+1⇒ a=−54⇒αβ=3a+4a+1=−1
If the product of the roots of the equation (a+1)x2+(2a+3)x+(3a+4)=0 be 2, then the sum of roots is