Question

$\text{If the scale for the figure is given as}$
$1in:50ft,\text{find the perimeter of the scale}$
$\text{drawing A'B'C'}.$

• A. 20 in
• B. 14 in
• C. 30 in
• D. 24 in

Answer 1

The correct option is D 24 in

To find the perimeter of the figure A'B'C', we need to find the lengths of all the sides of the triangle.

In the actul drawing:
AB = 300 ft.
BC = 400 ft.
AC = 500 ft.

$\text{Scale is}1in:50ft$


So, the dimensions in scale drawing are:
$\text{A'B' = scale}\times \text{AB}$
$=\frac{1}{50}\times 300$

$=6in$

$\text{B'C' = scale}\times \text{BC}$
$=\frac{1}{50}\times 400$

$=8in$

$\text{A'C' = scale}\times \text{AC}$
$=\frac{1}{50}\times 500$

$=10in$



$\therefore \text{Perimeter of the traingle A'B'C'}$
$=A^{\prime }{B}^{\prime }+B^{\prime }{C}^{\prime }+C^{\prime }{A}^{\prime }$
$=6+8+10$
$=24in$