The correct option is B c^2/r^2Since, ABC∼ PQR Therefore, a/p=b/q=c/r Also, we know that Ar ABC/Ar PQR=(a/p)^2=(b/q)^2=(c/r)^2 ...

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Question

$If △ A B C \sim △ P Q R,$
then, $\frac{A r △ A B C}{A r △ P Q R} =$ .

\frac{p}{b}

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\frac{c^{2}}{r^{2}}

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\frac{a}{p}

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Solution

The correct option is B $\frac{c^{2}}{r^{2}}$
Since, $△ A B C \sim △ P Q R$
Therefore,
$\frac{a}{p} = \frac{b}{q} = \frac{c}{r}$

Also, we know that
$\frac{A r △ A B C}{A r △ P Q R} = (\frac{a}{p})^{2} = (\frac{b}{q})^{2} = (\frac{c}{r})^{2}$

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Question 9

In $Δ P Q R$ ,

a) PQ - QR > PR
b) PQ + QR < PR
c) PQ - QR < PR
d) PQ + PR < QR

⎡ ⎢ ⎣ \begin{matrix} - q r & p (q + r) & p r + p q p q + q r & - p r & p q + q r q r + p r & q r + p r & - p q \end{matrix} ⎤ ⎥ ⎦

| A |

Q R S, Q R

R S, Q R = 12

R S = 12 \sqrt{3}

Q R S

{PR}^{2} = {PS}^{2} + QR \times ST + {(\frac{QR}{2})}^{2}

{PQ}^{2} = {PS}^{2} - QR \times ST + {(\frac{QR}{2})}^{2}

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