Question

$\text{If two adjacent sides of a rectangle}\text{measure}(2x^2+y)m\text{and}(x^2-y)m,\text{then find its perimeter.}$

• A. $6x^{2}m$
• B. $-6x^{2}m$
• C. $(6x^2-4y)m$
• D. $(6x^2+4y)m$

Answer 1

The correct option is A

$6x^{2}m$

$\text{Perimeter of a rectangle is 2 (l + b),}\text{where l = length and b = breadth.}$

Let us consider,
$l=2x^2+y\text{and}b=x^2-y$

$\text{Perimeter}=2\times (2x^2+y)$ + $2\times (x^2-y)$

= ($4x^2+2y$) +( $2x^2-2y$)

= $4x^2+2x^2+2y-2y$

= $6x^{2}m$