The correct option is A x−1
Since (x-3) and (x-2) are the factors of the given polynomial, the product of (x-3) and (x-2) (x−3)(x−2)=x2−2x−3x+6=x2−5x+6will also be a factor of the polynomial.
Now, for finding the third factor,divide the polynomialx3−6x2+11x−6 by (x2−5x+6).
x2−5x+6x−1)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x3−6x2+11x−6 −x3∓5x2± 6x +0–––––––––––––––––––––– −x2 + 5x− 6∓x2 ± 5x ∓6––––––––––––––––– 0
∴(x−1) is the third factor.