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Question

If x=13 is a solution of the equation ax2+(a1)x+4=a, find the value of a


A

9

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B

59/8

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C

33/5

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D

23/7

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E

33/7

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Solution

The correct option is C

33/5


Given x=13 and ax2+(a1)x+4=aa×(13)2+(a1)13+4=0a9+a13+4=aa+3a3+369=a4a+33=9a5a=33a=335=635


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