If x=13 is a solution of the equation ax2+(a−1)x+4=a, find the value of a
9
59/8
33/5
23/7
33/7
Given x=13 and ax2+(a−1)x+4=a⇒a×(13)2+(a−1)13+4=0⇒a9+a−13+4=a⇒a+3a−3+369=a⇒4a+33=9a⇒−5a=−33⇒a=335=635