If x+iy=(1+i)(1+2i)(1+3i),then x2+y2
∵ x+iy=(1+i)(1+2i)(1+3i)
Taking modulus on both the sides :
|x+iy|=|(1+i)(1+2i)(1+3i)|⇒ √x2+y2=√12+12√12+22√12+32⇒ √x2+y2=√2√5√10⇒ √x2+y2=√100
Squaring both the sides,
⇒ x2+y2=100