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Question

If x+iy=(1+i)(1+2i)(1+3i),then x2+y2

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Solution

x+iy=(1+i)(1+2i)(1+3i)

Taking modulus on both the sides :

|x+iy|=|(1+i)(1+2i)(1+3i)| x2+y2=12+1212+2212+32 x2+y2=2510 x2+y2=100

Squaring both the sides,

x2+y2=100


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