Question

$\text{If}x\text{and}y\text{vary inversely, then find}$
$x_2\text{and}{y}_3.$

x	25	$x_2$	$\frac{55}{2}$
y	60	55	$y_3$

• A. $x_2=\frac{30}{11}{y}_3=\frac{60}{11}$
• B. $x_2=\frac{300}{11}{y}_3=\frac{610}{11}$
• C. $x_2=\frac{250}{11}{y}_3=\frac{600}{11}$
• D. $x_2=\frac{300}{11}{y}_3=\frac{600}{11}$

Answer 1

The correct option is D $x_2=\frac{300}{11}{y}_3=\frac{600}{11}$

Given,
$x\text{and}y\text{vary inversely.}$
$\therefore x_1\times y_1=x_2\times y_2=x_3\times y_3$

Given,
$x_1=25$
$y_1=60$
$y_2=55$
$x_3=\frac{55}{2}$

So,
$x_2=\frac{x_1\times y_1}{y_2}$

$\Rightarrow x_2=\frac{25\times 60}{55}=\frac{300}{11}$

$y_3=\frac{x_1\times y_1}{x_3}$

$\Rightarrow y_3=\frac{25\times 60}{\frac{55}{2}}=\frac{600}{11}$