$If x is multiplied with the sum of 11 x^{2} - 8 x + 4$
$and 6 x^{2} + 7 x - 10, then find the product.$

17 x^{3} - x^{2} - 6 x

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17 x^{2} - x + 6

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17 x^{2} + x - 6

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17 x^{2} - x - 6

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Solution

The correct option is A $17 x^{3} - x^{2} - 6 x$
$11 x^{2} - 8 x + 4$ +
$6 x^{2} + 7 x - 10 - -------------- -$
$17 x^{2} - x - 6$

Now, multiplying
$17 x^{2} - x - 6 b y x,$

we get,
$x (17 x^{2} - x - 6) = (x \times 17 x^{2}) + (x \times - x) + (x \times - 6) = 17 x^{3} - x^{2} - 6 x$

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Similar questions

10 - 7 x = 8 x + 5

x^{2} - y^{2}

7 x + 8 y = 5

8 x + 7 y = 10

8 x = π

cos 7 x + cos x = 0

$Find the sum of$
$(11 x^{2} - 8 x + 4) and (6 x^{2} + 7 x - 10) .$

f (2)

f (x) = x^{3} + 7 x^{2} - 8 x + 9

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