$If y = 2^{2^{x}}, t h e n \frac{d y}{d x} =$

$y (l o g_{10} 2)^{2}$

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$y (l o g_{ε} 2)^{2}$

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$y 2^{x} (l o g_{ε} 2)^{2}$

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$y (l o g_{ε} 2)$

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Solution

The correct option is C
$y 2^{x} (l o g_{ε} 2)^{2}$

$y = 2^{2^{x}} \Rightarrow \frac{d y}{d x} = 2^{2 x} {.2}^{x} (l o g 2)^{2}$

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