If y - 2- then find the value ofxy2 - 2x-x-

Given, the expression is xy^2+2x/x. Taking x common from the numerator, we get x(y^2+2)/x=(y^2+2). Now substituting y=2 in the above equation, we get, (y^ ...

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Standard VIII

Mathematics

Factorisation by Common Factors

If y = 2, the...

Question

$If y = 2, then find the value of \frac{(x y^{2} + 2 x)}{x} .$

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Solution

The correct option is A 6
$Given, the expression is \frac{x y^{2} + 2 x}{x} .$

$Taking x common from the numerator, we get \frac{x (y^{2} + 2)}{x} = (y^{2} + 2) .$

$Now substituting y = 2 in the above equation, we get, (y^{2} + 2) = 2^{2} + 2 = 4 + 2 = 6$

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If y=2,then find the value of(xy2+2x)x.

The correct option is A 6Given, the expression is xy2+2xx. Taking x common from the numerator, we get x(y2+2)x=(y2+2). Now substituting y=2 in the aboveequation, we get, (y2+2)=22+2=4+2=6

$If y = 2, then find the value of \frac{(x y^{2} + 2 x)}{x} .$

The correct option is A 6
$Given, the expression is \frac{x y^{2} + 2 x}{x} .$

$Taking x common from the numerator, we get \frac{x (y^{2} + 2)}{x} = (y^{2} + 2) .$

$Now substituting y = 2 in the above equation, we get, (y^{2} + 2) = 2^{2} + 2 = 4 + 2 = 6$