Question

$\text{In a cam-follower mechanism the follower needs to rise through 20 mm during}{60}^{\circ }\text{of cam rotation, the first}{30}^{\circ }\text{with a constant acceleration and then retardation of equal magnitude for the next}{30}^{\circ }\text{. The cam rotates at uniform speed of 300 rpm. The maximum velocity of the follower during the rise period is}$

• A. 1.2 m/s
• B. 0.6 m/s
• C. 1.6 m/s
• D. 2.6 m/s

Answer 1

The correct option is A 1.2 m/s

Given,
$\text{Rise,}h=20\text{mm}=0.02\text{m}$

$\text{Angle of ascent,}{\varphi }_a={60}^{\circ }=\frac{\pi }{3}\text{rad with constant acceleratio and deceleration}$

$N=300\text{rpm,}$

$\omega =\frac{2\pi N}{60}=\frac{2\pi \left(300\right)}{60}=10\pi \text{rad/s}$

$V_{\text{max}}=\frac{2h\omega }{{\varphi }_a}=\frac{2\times 0.02\times 10\pi }{\frac{\pi }{3}}=1.2\text{m/s}$