In a triangle ABC - AB -1- AC -2 and - A -60- its largest angle is equal toA- 75-B- 90-C- 135-D- 120-

The correct option is B 90° Given, c = 1, b = 2 ∠ A=60^0 ∴cosA=4+1 a^2/4=1/2 ⇒5 a^2=2 ⇒a=√(3) Clearly a^2+c^2=b^2 ∴ΔABC is a right triangle. ⇒largest angle=90^ ...

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Standard VII

Mathematics

Corresponding Parts of Congruent Triangles

In a triangle...

Question

$In a triangle ABC, AB = 1, AC = 2 and ∠ A = 60^{0}, its largest angle is equal to$

75°

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90°

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120°

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135°

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Solution

The correct option is B
90°

$Given, c = 1, b = 2 ∠ A = 60^{0} ∴ c o s A = \frac{4 + 1 - a^{2}}{4} = \frac{1}{2} \Rightarrow 5 - a^{2} = 2 \Rightarrow a = \sqrt{3} Clearly a^{2} + c^{2} = b^{2} ∴ Δ ABC is a right triangle. \Rightarrow largest angle = 90^{0}$

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In a triangle ABC, AB = 1, AC = 2 and∠A=600,its largest angle is equal to

The correct option is B 90° Given, c = 1, b = 2∠A=600∴cosA=4+1−a24=12⇒5−a2=2⇒a=√3Clearly a2+c2=b2∴ΔABC is a right triangle.⇒largest angle=900

$In a triangle ABC, AB = 1, AC = 2 and ∠ A = 60^{0}, its largest angle is equal to$

The correct option is B
90°

$Given, c = 1, b = 2 ∠ A = 60^{0} ∴ c o s A = \frac{4 + 1 - a^{2}}{4} = \frac{1}{2} \Rightarrow 5 - a^{2} = 2 \Rightarrow a = \sqrt{3} Clearly a^{2} + c^{2} = b^{2} ∴ Δ ABC is a right triangle. \Rightarrow largest angle = 90^{0}$