$In an AM superheterodyne receiver that local osicllator frequency of the mixer is set at the higher of the two possible values, such that f_{L O} > f_{c} always. The intermediate frequency (IF) of the receier is 450 kHz and the receiver is tuned to a station carrier frequency of 600 kHz. If the RF amplifier is failed to reject the image frequency and the loaded quality factor of the RF amplifier is 100, then the image rejection ratio of the receiver at the selected station frequency will be_______$
210

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Solution

The correct option is A 210
$Q = 100 f_{s i} = f_{c} + 2 (I F) = 600 + 2 (450) = 1500 k H z P = \frac{f_{s i}}{f_{c}} - \frac{f_{c}}{f_{s i}} = \frac{1500}{600} - \frac{600}{1500} = 2.1 Image rejection ratio, α = \sqrt{1 + P^{2} Q^{2}} = \sqrt{1 + (21 \times)^{2}} = 210$

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The intermediate frequency (IF) of an AM superheterodyne receiver is 450 kHz and the local oscilliator frequency (F_{L O}) of the mixer is set at the higher of the two possible values, such that f_{L O} > f_{c} always. If the carrier frequency (f_{c}) of the received signal is 650 kHz, then the carrier frequency of the corresponding image signal will be equal to_______kHz.

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