In any ABC - a b cos C - c cos B equalsA- b2-c2B- 1-b-1-cC- 1-b2-1-c2D- b2-c2

The correct option is D b2 c2 a(b cos C c cos B)=ab cos C ac cos B =a^2+b^b c^2 a^2+c^2 b^2/2 ...

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Common Ratio

In any ABC , ...

Question

$In any △ A B C, a (b c o s C - c c o s B) e q u a l s$

b² + c²

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b² - c²

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Solution

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Similar questions

Δ A B C, a (b c o s C - c c o s B)

△ A B C

a (b cos C - c cos B) = b^{2} - c^{2}

Δ A B C, a (b c o s C - c c o s B)

a (b cos C - c cos B) = b^{2} - c^{2}

Mark the correct alternative in each of the following :

$I n a n y Δ A B C, a (b c o s C - c c o s B) =$

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