Question

$\text{In}\Delta \text{ABC, a = 13 cm, b = 12 cm and c = 5 cm. Then, the distance of A from BC is}$

• A.
• B. 60/13 cm
• C. 65/12 cm
• D. 144/13 cm

Answer 1

The correct option is B

60/13 cm

$\text{Since, a = 13 cm, b = 12 cm, c = 5 cm}\text{Now,}(13{)}^2=(5{)}^2+(12{)}^2\text{So},\Delta \text{ABC is a right angled triangle}\therefore Area=\frac{1}{2}\times 5\times 12=30c{m}^2\text{Again, area}=\frac{1}{2}\times BC\times AD\Rightarrow 30=\frac{1}{2}\times 13\times AD\Rightarrow AD=\frac{60}{13}cm$