InΔABC, a = 13 cm, b = 12 cm and c = 5 cm. Then, the distance of A from BC is
A
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B
60/13 cm
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C
65/12 cm
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D
144/13 cm
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Solution
The correct option is B
60/13 cm
Since, a = 13 cm, b = 12 cm, c = 5 cmNow,(13)2=(5)2+(12)2So,ΔABC is a right angled triangle∴Area=12×5×12=30cm2Again, area=12×BC×AD⇒30=12×13×AD⇒AD=6013cm