In given figure, ABCD is a rhombus. If ∠OAB=40∘,then find the value of x.
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Solution
Given: ∠OAB=40∘
We know that diagonals of a rhombus are perpendicular to each other.∴∠AOB=90∘ In △AOB, By angle sum property,∠OAB+∠AOB+∠OBA=180∘40∘+90∘+x=180∘ x=180∘−130∘ x=50∘