$In parallelogram A B C D, A P and C Q are perpendicular to diagonal B D . Statement 1: Δ A P B ≅ Δ C Q D Statement 2: SSS congruence is applied$

Pick the correct option.

Both statements are correct

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Both statements are false

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Statement 1 is correct but 2 is false

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Statement 1 is false but 2 is correct

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Solution

The correct option is C Statement 1 is correct but 2 is false
$In Δ A P B and Δ C Q D, A B = C D (opposite sides of a parallelogram) . ∠ A B P = ∠ C D Q (alternate angles) . ∠ A P B = ∠ C Q D (both are right angles) . ∴ Δ A P B ≅ Δ C Q D$
(using AAS criterion)
Hence, statement 1 is correct but statement 2 is false

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Similar questions

In parallelogram A B C D, A P and C Q are perpendicular to diagonal B D .

It can be proved that:

Statement 1: Δ A P B ≅ Δ C Q D,

Statement 2: RHS congruence is applied

5 x + 6 = 0

5 x + 6 = 0

Choose the correct option.

Statement $1 : (p \land \sim q) \land (\sim p \land q)$ is a fallacy.

Statement $2 : (p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow\sim p)$ is a tautology.

Statement 1: If B^{- 1} = ⎡ ⎢ ⎣ \begin{matrix} 0 & 6 & 7 8 & 9 & 10 11 & 12 & 13 \end{matrix} ⎤ ⎥ ⎦ and A = ⎡ ⎢ ⎣ \begin{matrix} 5 & 6 & 7 8 & 9 & 10 11 & 12 & 13 \end{matrix} ⎤ ⎥ ⎦, then (A B)^{- 1} does not exist Statement 2 : Since | A | = 0, (A B)^{- 1} = B^{- 1} A^{- 1} is meaningless.

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