Question

$\text{In the below figure, if}△ABC\cong △XYZ,\text{then find the}\text{value of x is.}$

Answer 1

$\text{Given,}△ABC\cong △XYZ$

We know that, the corresponding parts of congruent triangles are equal.
$\text{So,}\angle CAB=\angle ZXY={30}^{\circ }$

$\text{In}△ABC$,
$\angle CAB$ + $\angle ABC$ + $\angle BCA$ = ${180}^{\circ }$
${30}^{\circ }+x+{70}^{\circ }={180}^{\circ }$
$x=({180}^{\circ }-{30}^{\circ }-{70}^{\circ })={80}^{\circ }$