Question

$\text{In the figure shown above, the output voltage}{V}_0\text{is\_\_\_\_\_\_V. (Assume op-amps are ideal)}$

• A. 0

Answer 1

The correct option is A 0

$\text{Due to virtual short,}{V}_A=2\text{V and}{V}_C=2V$
Applying KCL at node A, we get
$\frac{0-2}{2\text{k}\Omega }=\frac{2-V_B}{2\text{k}\Omega }+\frac{2-2}{1\text{k}\Omega }$
$V_B=4\text{Volts}$
Applying KCL at node C, we get
$\frac{V_C-2}{1\text{k}\Omega }+\frac{V_C-V_0}{2\text{k}\Omega }+\frac{V_C-V_B}{2\text{k}\Omega }=0$
$\frac{2-2}{1\text{k}\Omega }+\frac{2-V_0}{2\text{k}\Omega }+\frac{2-4}{2\text{k}\Omega }=0$
$V_0=0\text{Volt}$