In the following figure, triangle AXY is isosceles with ∠AXY=∠AYX.
If BXAX=CYAY, then
Here, BXAX=CYAY
⇒AXBX=AYCY
(By taking reciprocals on both sides)
∴XY||BC
(By converse of basic proportionality theorem)
∴∠B=∠AXY and ∠C=∠AYX
(Corresponding angles)
But ∠AXY=∠AYX (Given)
⇒∠B=∠C
⇒AC=AB(Sides opposite to equal angles are equal)
∴ΔABC is an isosceles triangle.