The correct option is D BC is parallel to PG.
Two triangles on the same base (or equal bases) and between the same parallels have equal areas.
∴ If ar(△ BUG)=ar(△ CUP),
(△BUG) and (△CUP) have the same base and are between the same parallels.
⇒BU is equal to CU and BC is parallel to PG.