Question

$\text{In the given figure, D is a point on side BC of a}\Delta ABC\text{and E is a point such that CD = DE.}\text{Prove that AB + AC}>BE.$

Answer 1

Given: CD = DETo prove: AB + AC > BE
Proof:
In ∆ABC,
AB+AC>BC----1
In ∆BED,
BD+CD>BE⇒BC>BE----2
From (1) and (2), we get
AB + AC > BE