In the given figure, DE || BC. If AD = 6 cm,AB = 24 cm and DE = 5 cm, then BC = ____ cm.
20
Consider ΔADE and ΔABC,DE || BC(Given)
∠ADE=∠ABC∠AED=∠ACB(Corresponding angles are equal)
∠DAE=∠BAC (Common angle)
∴△ADE∼△ABC (AA Similarity)
So, DEBC=ADAB
⇒BC=DE×ABAD
⇒BC=5×246
⇒BC=20 cm