In the given figure- - ABC and - OBC are both isosceles- It can be concluded that- - AOB - AOC-AB - AO- ABO - - ACO- AOB is not congruent to- AOC-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

SSS Congruency Postulate

In the given ...

Question

$In the given figure, Δ A B C and Δ O B C are both isosceles.$
$It can be concluded that:$

$Δ A O B ≅ Δ A O C$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

AB = AO

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$∠ A B O = ∠ A C O$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$Δ A O B is not congruent to Δ A O C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A
$Δ A O B ≅ Δ A O C$

C
$∠ A B O = ∠ A C O$

$In Δ A O B and Δ A O C, A B = A C (Sides of isosceles Δ A B C) . O B = O C (Sides of isosceles Δ O B C) . A O i s c o m m o n ∴ Δ A O B ≅ Δ A O C (by SSS congruence)$
And $∠ A B O = ∠ A C O$ ( By CPCT)

Suggest Corrections

Similar questions

$In the given figure, Δ A B C and Δ O B C are both isosceles.$
$It can be concluded that:$

Q. In the given figure,

A B ∥ C D

and AB = CD. [3 MARKS]

Prove that: (i)

Δ A O B ≅ Δ D O C

(ii) AO = DO

(iii) BO = CO

$In the given figure, Δ A B D is an isosceles triangle with A B = A D . A median is drawn from A to side B D at C . Which of the following option(s) is/are correct?$

Q. If AB = DC, ∠ABO = ∠DCO = 90°, and OD = 5 cm. Find the length of AO.

Join BYJU'S Learning Program

In the given figure, ΔABC and ΔOBC are both isosceles. It can be concluded that:

The correct options are A ΔAOB≅ΔAOC C ∠ABO=∠ACO In ΔAOB and ΔAOC,AB=AC(Sides of isosceles ΔABC).OB=OC(Sides of isosceles ΔOBC).AO is common∴ΔAOB≅ΔAOC(by SSS congruence) And ∠ABO=∠ACO ( By CPCT)

$In the given figure, Δ A B C and Δ O B C are both isosceles.$
$It can be concluded that:$

The correct options are
A
$Δ A O B ≅ Δ A O C$

C
$∠ A B O = ∠ A C O$

$In Δ A O B and Δ A O C, A B = A C (Sides of isosceles Δ A B C) . O B = O C (Sides of isosceles Δ O B C) . A O i s c o m m o n ∴ Δ A O B ≅ Δ A O C (by SSS congruence)$
And $∠ A B O = ∠ A C O$ ( By CPCT)